The daily report changes a fee of $525 plus $75 per week to run an advertisement. the press charges $150 per week. write an inequality that can be solved to find the number of weeks an ad must run to make the total cost of running an ad in the daily reports less than the cost in the press.

525 + 75w < 150w

Step-by-step explanation:

Let the number of weeks to run the ad be "w"

The cost of daily report would be:

525 + 75w

The cost of press would be:

150w

We need the daily report to be LESS THAN the cost of press, thus:

525 + 75w < 150w

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x