4,320 is divisible by
a. 3
b. 9
c. 10
explain your reasoning for your choice(s).

Hello!

So our number is 4,320, and we want to know if its divisible by some numbers:

a) by 3, so we know that every number is divisible by 3 if the addition of all te decimals that conform it are a multiple of 3 ( for example 3, 6, 9, 12...), this is:

4 + 3 + 2 + 0 = 9, 9 is a multiple of 3, then 4320 is divisible by 3.

and we know that 3 * 1000 = 3000

3*400 = 1200

3*40 = 120

then 3*(40 + 400 + 1000) = 4320

then 4320/3= 1440

b) by 9.

We already know that if the addition of all the decimals is a multiple of 3, then the number is divisible by 3. We also know that 9 = 3*3, and we know that 4320/3 = 1440

now; 4320/9 = 4320/(3*3) = 1440/3

now we need to see if 1440 is divisible by 3, then we use the same method as before, 1 + 4 + 4+ 0 = 9, then 1440 is divisible by 3

c) by 10, every number that ends in a 0 is divisible by 10, here 4320/10 = 432, so dividing by 10 "removes" the last 0 in our number (and multiplying by 10 ads a 0 to the right side of our number)

in mathematics, a constraint is a condition of an optimization problem that the solution must satisfy. there are several types of constraints—primarily equality constraints, inequality constraints, and integer constraints. the set of candidate solutions that satisfy all constraints is called the feasible set.

hoped i'm right lol

step-by-step explanation:

the answer is 89 d

i took the test