In a certain algebra 2 class of 29 students, 14 of them play basketball and 8 of them play baseball. there are 9 students who play neither sport. what is the probability that a student chosen randomly from the class plays both basketball and baseball?

  2/29

Step-by-step explanation:

If 9 play none, of the 29 students, 29-9 =20 play at least one. If 14 play basketball, then 20-14 = 6 play only baseball. Since 8 play baseball, there must be 8-6 = 2 who play both baseball and basketball.

Choosing at random, the probability is 2/29 that a student will be chosen who plays both sports.

p(x)= 8 x³ - 36 x² + 54 x - 27

q(x) = 2 x -3

you can check your mistake and then you can choose the correct option.

dividend =   8 x³ - 36 x² + 54 x - 27

divisor = 2 x -3

if you want to find quotient, proceed as follows

q(x)= 0

2 x - 3=0

x =

now , i have used division method , to find quotient and remainder