How does changing the function from f(x) = 2 sin 4x to g(x) = 2 sin 4x + 3 affect the range of the function? the function shifts up 3 units, so the range changes from −2 to 2 in f(x) to 1 to 5 in g(x). the function shifts up 3 units, so the range changes from −1 to 1 in f(x) to 2 to 4 in g(x). the function shifts up 4 units, so the range changes from −2 to 2 in f(x) to 2 to 6 in g(x). the function shifts up 4 units, so the range changes from −1 to 1 in f(x) to 3 to 5 in g(x).

Step-by-step explanation:

Consider the parent function

f(x) = sin 4x has range as -1 to 1

When sin4x is multiplied by 2, we have range changes to -2 to 2

When the graph is shifted up by 3 units we get

range changes minimum from -2 to -2+3=1 and maximum as 2+3=5

So range is in the interval

[1,5]

Option

he function shifts up 3 units, so the range changes from −2 to 2 in f(x) to 1 to 5 in g(x)is right

395.84

step-by-step explanation:

2πrh+2πr²

2 (pie)(radius)(height)+2(pie)(radius)^2

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.