Use the quadratic polynomial 3x2−3x−90 to answer the questions.

a: which summary correctly applies the fundamental theorem to the quadratic polynomial?

b: which statement correctly verifies the application of the fundamental theorem of algebra?

select one answer for question a, and select one answer for question b.

b: the quadratic equation 3x2−3x−90=0 has two real solutions, x=6 or x=−5, and therefore has two real roots.
b: the quadratic equation 3x2−3x−90=0 has one real solution, x=5, and therefore has one real root with a multiplicity of 2.
b: the quadratic equation 3x2−3x−90=0 has two real solutions, x=−6 or x=5, and therefore has two real roots.
a: this polynomial has a degree of 2, so the equation 3x2−3x−90=0 has more than two roots.
a: this polynomial has a degree of 2, so the equation 3x2−3x−90=0 has exactly two roots.
a: this polynomial has a degree of 2, so the equation 3x2−3x−90=0 has two or fewer roots.

10% of increase is the final answer! : )

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.