consider the functions f(x)=3x+30 and g(x)=x^2+20. at what positive integer value of x does the quadratic function, g(x) begin to exceed the linear function f(x)?

x=5

Step-by-step explanation:

We are given that  

We have to find the positive  integer value of x for which the quadratic function g(x) begin to exceed the linear function f(x).

Interval (

Therefore , g(x) exceed f(x) in the interval (.

g(x) begin to exceed the linear function at x=5

Byou start by adding them all and setting them equal to 180 since that is half of the total degrees in a circle.(2x+8) + (3x-14) + (3x-14) = 1808x-20 = 1808x = 200x = 25

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm