Two number cubes are rolled for two seperate events: event a is the event that the sum of numbers on both cubes is less than 10. event b is the event that the sum of numbers on both cubes is a multiple of 3. complete the conditional-probability formula for event b givem thaf event a occurs first by writing a and b in the blanks:

Probability of getting sum less than

10 =  \frac{30}{36}=  \frac{5}{6}

Probability of getting a multiple of 3= \frac{20}{36}= \frac{5}{9}  

(A) P(B|A)= \frac{P(B∩A)}{P(A)} = \frac{15/36}{30/36}= \frac{15}{30}=0.5  

(B)P(A|B)= \frac{P(A∩B)}{P(B)}= \frac{15/36}{5/9}=0.75  

(C) {A∩B} = {3, 6, 9, 12, 15, 18}

(D) {A} = {1, 2, 3, 4, 5 ,6, 7, 8, 9}

-Hope this helps-

6 on both sides and twelve on the top and the bottom

step-by-step explanation:

the answer would be c:   ax + b = ax + c

step-by-step explanation: