Agolfer’s arm rotates 1/2 of a revolution in 1/10 of a second. if the angular displacement is measured in radians, which statements are true? check all that apply.

the angular velocity is 10π rad/sec.
the angular velocity is 10π rad/min.
the angular velocity is 60π rad/min.
the angular velocity is 600π rad/sec.
the angular velocity is 600π rad/min.

10π rad/sec and  60π rad/min.

Step-by-step explanation:

1 revolution is 360°, so 1/2 rev is 180°.

Let's convert 180° into radians:

180° x π / 180 = π rad

Having both values, radians and time, the relation makes the angular velocity.

1/10π rad/sec

Multiply by 10 to eliminate the fraction:

10π rad/sec

Multiply by 60 to convert sec to min:

60π rad/min

The angular velocity is 10π rad/sec.

The angular velocity is 600π rad/min.

Step-by-step explanation:

As we know that angular velocity is the ratio of change in angle and time.

Here golfer’s arm rotates 1/2 of a revolution, also revolution has 360° angle. thus 1/2 of a revolution = 180°.

Changing degree into radians, 180° = π rad

and time is 1/10 of a second, ⇒ t = 0.1 sec

Hence, Angular Velocity = π ÷ 0.1 = 10π rad/sec.

And for changing the second unit into minute, multiply it by 60.

Angular Velocity = 600π rad/min.

in 4 days he will run   12/14

step-by-step explanation:

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