12x−39≤9 and−4x+3< −6, just solving for x

answer asap

Solving for x in 12x − 39 ≤ 9 and −4x + 3 < −6 we get 2.25 < x ≤ 4

Solution:

Need to find the value of x which satisfies following two given expressions

12x − 39 ≤ 9      (1)

−4x + 3 < −6     (2)

Lets first solve expression (1)

12x − 39 ≤ 9  

Adding 39 on both sides , we get

12x−39 + 39  ≤ 9  +39

=>12x ≤ 48

=> x  ≤ 48/12

=> x ≤ 4    

Now solving expression (2)

−4x+3<−6      

=> -4x < -6 – 3

=> -4x < -9  

=> 4x > 9

=> x > 9/4

=> x > 2.25

So from solution of expression (1) and (2) , we get x ≤ 4   and x > 2.25

Hence required value of x is 2.25 < x ≤ 4.  

answer: .75 km

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!