The equation of a parabola is shown.
x-7=3/4y^2
what are the coordinates of the focus?
a.) (71/3,0)
b.) (7,-1/3)
c.) 73/4,0)
d.) 7,-3/4)

The axis of symmetry for this parabola is the x-axis. The general form of the equation is:
4p(x-h) = (y-k)^2
where the focus has the coordinates of (h+p,k)

Manipulating the given equation to the general form:
4(1/3)(x-7)^2 = (y - 0)^2

Therefore the coordinates of the focus is:
(7+(1/3),0)

The answer is A.) (71/3,0)