John saves n$ 3500 the first month and every month later decreases it by n$ 75. a) how much will john save in the 11th month? (5) b) how much will he save after two (2) years?

(a) $4250,

(b) $5225.

Step-by-step explanation:

Let n represent number of months.

We have been given that John saves $3500 the first month and every month later decreases it by $75.

First of all, we will find formula of John's savings in n months using arithmetic progression, where, 1st term is 3500 and common difference is 75.

, where,

n = Number of terms in a sequence,

d = Common difference.

(a) To find John's savings in 11 months, we will substitute in above formula.

Therefore, John would have saved $4250 in the 11th month.

(b) To find John's savings after 2 years, we will substitute in above formula.

Therefore, John would have saved $5225 in 2 years.

look at the picture.

y-intercept for the function on a picture is 4 → point (0, 4).

y-intercept for the function

is for x = 0. substitute:

y-intercept is 8 → point (0, 8).