The surface areas of two similar figures are given. the volume of the larger figure is given. find the volume of the smaller figure. s. a. = 192 m s. a. = 1728 m² v = 4860 m3

The volume of smaller figure is 180 m³

Step-by-step explanation:

Consider the provided information.

The ratio of the surface areas is equal to the square of scale factor K.

let K₁ and K₂ is the scale factor

Thus

Substitute the respective values as shown.

It is given that the volume of larger figure is 4860 m³.

Let V₁ and V₂ is the volume of small and larger figure respectively.

The ratio of the volume is equal to the third power of scale factor K.

Thus

Substitute the respective values as shown.

Hence, the volume of smaller figure is 180 m³

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.

answer: the center is the median and/or mean of the data. the spread is the range of the data. and, the shape describes the type of graph. the four ways to describe shape are whether it is symmetric, how many peaks it has, if it is skewed to the left or right, and whether it is uniform. good luck

step-by-step explanation: