In a small private school, five students are randomly selected from eighteen available students. what is the probability that they are the five youngest students?

1 / 8568

Step-by-step explanation:

The number of combinations is:

₁₈C₅ = (18! / (5! (18−5)!)

₁₈C₅ = 8568

There are 8568 possible groups of 5 that can be selected from 18.  Only 1 of those groups contains the five youngest students.  So the probability is:

P = 1 / 8568 ≈ 0.0117%

7.25

step-by-step explanation:

we know that 7 equals to 7.0. we also know that 1/4=0.25. so we can add the two together and we get 7.25

answer: c

substitute in the values.

for a:

f(0) = 0 + 9

f(0) = 9

a is a solution.

for b:

f(7) = 14 + 9

f(7) = 23

b is a solution.

for c:

f (3) = 6 + 9

f(3) = 15

c is not a solution. it's supposed to be 14.

for d:

f(2) = 4 + 9

f(2)= 13

d is a solution.