Let a(t) be the area of tissue culture at time t (in days). let the final area of the tissue when the growth is complete be 10 cm2. most cell divisions occur on the periphery of the tissue and the number of cells on the periphery is proportional to a. so, a reasonable model for the growth of tissue is obtained by assuming that the rate of growth is jointly proportional to va and 10 a a) formulate the differential equation that models this situation

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

well we know there are 4 clubs in 52 cards so it’s replaced so it should be 3/51

step-by-step explanation: