How do i solve this?

solve y′=(y−5)(y+5) if y(2)=0?

i used methods of separation and did a partial fraction integral and ended up with

(ln(y+5)-ln(y-5))/10 = x

i'm not sure if i did this correctly nor do i know how to solve for y at this point. send ! you.

Thus the solution of the differential becomes

\frac{y-5}{y+5}=e^{10x-20}

Step-by-step explanation:

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.