Solve the following pair of simultaneous equations.
2x + 3y = 6
3x - 2y = 22

(6, - 2 )

Step-by-step explanation:

Given the 2 equations

2x + 3y = 6 → (1)

3x - 2y = 22 → (2)

Eliminate the y- term by multiplying (1) by 2 and (2) by 3

4x + 6y = 12 → (3)

9x - 6y = 66 → (4)

Add (3) and (4) term by term

13x = 78 ( divide both sides by 13 )

x = 6

Substitute x = 6 into either of the 2 equations and solve for y

Using (1), then

(2 × 6) + 3y = 6

12 + 3y = 6 ( subtract 12 from both sides )

3y = - 6 ( divide both sides by 3 )

y = - 2

Solution is (6, - 2 )

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3

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