Acommittee of 2 people is to be chosen from 5 women and 5 men. what is the probability at least one man was chosen given at least one woman was chosen?

5/9

Step-by-step explanation:

At the beginning, there are 5 + 5 = 10 people to choose from. After one woman is chosen, that number goes down to 10 - 1  = 9 people. 5 men are still left to choose from, so there is a 5/9 chance at least one man will be selected as the other committee member.

5/7

Step-by-step explanation:

Number of women = 5

Number of men = 5

2 people is to be chosen to form a committee.

Let as assume

A : At least one man was chosen

B : At least one woman was chosen

A ∩ B : Exactly one man and one woman was chosen

P(B) = Exactly one woman was chosen + Two women was chosen

We need to find the probability at least one man was chosen given at least one woman was chosen.

Therefore, the required probability is 5/7.

2x3 – 6x2 – 14x + 24 square centimeters

if i'm wrong i'm sorry : )

81 seats

step-by-step explanation:

if you multiply 0.65 times 125 then you get 81.5 seats. well since you can't have half of a seat you have to round down and get 81 seats in the no children zones. that leave 44 seats outside of the no children zone.