Mathematics, 02.10.2019 06:10 bks53

Between 10 p. m. and
7: 45 a. m., the water level in a swimming pool
decreased by 13/16 inch.
assuming that the water level decreased at a
constant rate, how much did it drop each hour?

Answers: 1

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Answers

Answer from: dan7478

The water level dropped $\frac{1}{12}$ inch each hour

Step-by-step explanation:

- Between 10 P.M. and 7:45 A.M., the water level in a swimming pool

decreased by 13/16 inch

- Assuming that the water level decreased at a constant rate

- We need to find the drop each hour that means the unit rate of

decreased of the level of the water

- At first lets hind how many hours between 10 P.M. and 7:45 A.M.

∵ Between 10 P.M. and mid-night 2 hours

∵ Between mid-night and 7:45 A.M. 7 hours and 45 minutes

- Lets change 7 hours and 45 minutes to hours

∵ 1 hour = 60 minutes

∴ 45 minutes = 45 ÷ 60 = $\frac{3}{4}$ hours

∴ 7 hours and 45 minutes = $7\frac{3}{4}$ hours

∴ The total hours between 10 P.M. and 7:45 A.M. = 2 + $7\frac{3}{4}$ hours

∴ The total hours between 10 P.M. and 7:45 A.M. = $9\frac{3}{4}$

∵ The unit rate of decreased = The decreased level ÷ total hours

∵ The decreased level is $\frac{13}{16}$ inche

∵ The total hours = $9\frac{3}{4}$ hours

- Lets change the mixed number $9\frac{3}{4}$ to improper fraction

∵ $9\frac{3}{4}$ = $\frac{(9*4)+3}{4}$

∴ $9\frac{3}{4}$ = $\frac{39}{4}$

∵ The unit rate of decreased = $\frac{13}{16}$ ÷ $\frac{39}{4}$

- To solve the division of 2 fractions change the division sign to

multiplication sign and reciprocal the fraction after the division sign

∴ The unit rate of decreases = $\frac{13}{16}$ × $\frac{4}{39}$

∴ The unit rate of decreases = $\frac{1}{12}$ inch per hour

The water level dropped $\frac{1}{12}$ inch each hour

Answer from: calc14

$\frac{1}{12}$ inches per hour.

Step-by-step explanation:

Between 10 P.M. and 7:45 A.M., the water level in a swimming pool decreased by $\frac{13}{16}$ inch.

First we calculate the hours between 10:00 P.M and 7:45 A.M.

10:00 P.M. = 22:00 P.M.

10:00 p.m. + 2 hours = 12:00 a.m.

so 2 hours + 7 hours and 45 minutes = 9 hours 45 minutes

9 hours 45 minutes = $9\frac{3}{4}$ = $\frac{39}{4}$ hours

It takes $\frac{39}{4}$ hours to decrease the water level by $\frac{13}{16}$ inches.

In 1 hour the water level would decrease = $\frac{\frac{13}{16}}{\frac{39}{4} }$

= $\frac{13}{16}$ × $\frac{4}{39}$

= $\frac{13}{4\times 39}$

= $\frac{13}{156}$

= $\frac{1}{12}$ inches/hour

The water level decreased at a $\frac{1}{12}$ inches each hour.

Answer from: Quest

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)
I’m not sure how to solve these type of problems

I’m not sure how to solve these type of problems

Answer from: Quest

answer: it's d

step-by-step explanation:

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Between 10 p. m. and
7: 45 a. m., the water level in a swimming pool
decreased by 13/16 in...

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