Two projectiles are thrown with the same initial speed, one at an angle θ with respect to the level ground and the other at angle 90° − θ. both projectiles strike the ground at the same distance from the projection point. are both projectiles in the air for the same length of time?

Height is different for both .

The time in air are different for both.

Step-by-step explanation:

Given that initial velocity is same

Lets take initial velocity = u

One at  an angle θ.

other at angle 90° − θ.

Also given that their range are same

We know that

sin(180° − θ)=sin θ

So

Height in the air

We know that

sin(90° − θ)=cos θ

From above we can say that height is different for both .

Time:

sin(90° − θ)=cos θ

The time in air are different for both.

where are the choices?

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)