Solve the system.
x+3y= 22
2x -y=2
(7,5)
(2,2)
(4,6)
no solution

x = 4 , y = 6

Step-by-step explanation:

Solve the following system:

{x + 3 y = 22 | (equation 1)

2 x - y = 2 | (equation 2)

Swap equation 1 with equation 2:

{2 x - y = 2 | (equation 1)

x + 3 y = 22 | (equation 2)

Subtract 1/2 × (equation 1) from equation 2:

{2 x - y = 2 | (equation 1)

0 x+(7 y)/2 = 21 | (equation 2)

Multiply equation 2 by 2/7:

{2 x - y = 2 | (equation 1)

0 x+y = 6 | (equation 2)

Add equation 2 to equation 1:

{2 x+0 y = 8 | (equation 1)

0 x+y = 6 | (equation 2)

Divide equation 1 by 2:

{x+0 y = 4 | (equation 1)

0 x+y = 6 | (equation 2)

Collect results:

{x = 4 , y = 6

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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