In the figure, abcd is parallelogram. point o is the intersection point of diagonals ac and db, and dc=9 cm and bc=6cm. given that p(∆aod)=17cm, find p(∆aob)
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hello there!

i believe the answer is

(cot2+1)/sec2=cot2

    csc2/sec2=cot2

  (1/sin2)/(1/cos2)=cot2

  (1/sin2)(cos2/1)=cot2

  cos2/sin2=cot2

  (1/tan2)=cot2

  (cot2)=(cot2)

hope this !

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