Acoordinate plane, a curved line with a maximum value of (negative 1, 4) and minimum values of (negative 1.25, negative 16) and (2.5, negative 3), crosses the x-axis at (negative 2.1, 0), (0.25, 0), (1.75, 0), and (3, 0), and crosses the y-axis at (0, negative 3). which intervals show f(x) decreasing? check all that apply.

-edgunity

answer: i guess 105 degrees?

step-by-step explanation:

sorry i need the points

step-by-step explanation:

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english, cause i can’t you

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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