Factor completely 3x^4 - 30x^3 + 75x^2
3(x-5)^2
3x^2(x-5)^2
3x^2(x^2-10x+25)
3x^2(x+5)(x-5)

The answer to your question is:    3x² (x - 5) ²      

Step-by-step explanation:

Factor like terms                       3x⁴ - 30x³ + 75x²

                                                  3x² ( x² - 10x + 25)

Factor ( x² - 10x + 25)  = ( x - 5) (x - 5)  = (x - 5) ²

Finally                                        3x² (x - 5) ²              

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180