The height of an object t seconds after it is dropped from a height of 300 meters is s(t) = −4.9t2 + 300. (a) find the average velocity of the object during the first 6 seconds. -78.4 m/s (b) use the mean value theorem to verify that at some time during the first 6 seconds of fall, the instantaneous velocity equals the average velocity. find that time. 2.1 s

See it in the pic

Step-by-step explanation:

See it in the pic

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).