Aproduce supplier ships boxes of produce to individual customers. the distribution of weights of shipped boxes is approximately normal with mean 36 pounds and standard deviation 4 pounds. which expression represents the weight, in pounds, at the 75th percentile of the distribution?

(a) -1.96(4)+ 36
(b) -0.25(4) + 36
(c) 0.25(4)+ 36
(d) 0.67(4)+ 36
(e) 0.75(4)+ 36

Option D.

Step-by-step explanation:

Given information: The distribution of weights of shipped boxes is approximately normal.

Population mean = 36

Standard deviation = 4

We need to find the 75th percentile of the distribution

75% = 0.75

From z-table it is clear that the value of z at 0.75 is 0.674.

75th percentile = Mean + z value at 75%(Standard deviation)

75th percentile = 36 + 0.674(4)

In can be rewritten as

75th percentile = 0.67(4) + 36

Therefore, the correct option is D.

step-by-step explanation:

the multiplicative inverse of a fraction a/b is b/a. for the multiplicative inverse of a real number, divide 1 by the number. for example, the reciprocal of 5 is one fifth 1/5 or 0.2, and the reciprocal of 0.25 is 1 divided by 0.25, or 4.

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.