The number line shows the distance in meters of two skydivers, a and b, from a third skydiver located at point x: a horizontal number line extends from negative 3 to positive 3. the point labeled as a is at negative 2.5, the point 0 is labeled as x, and the point labeled b is at 0.5. write an expression using subtraction to find the distance between skydivers a and b. show your work and solve for the distance using additive inverses. (5 points)

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

step-by-step explanation: