Aneed . show work step by step

1)in a trapezoid with a height of 5 meters, one of the bases is three times the lenght of the other base. solve for the lenghts of the two bases if a=70m^2.

2)in a trapezoid with a height of 10 feet, one base is 4 feet longer than the other base. solve for the lenghts of the two bases if a=120ft^2

1) 8.75 m   ,    26.25 m

               2) 4ft, 8ft

Step-by-step explanation:

1) First, you can find lenght of bases.

    70 / 2 = 35

  So you can set x for shorter base and 3x for longer base.

    x + 3x = 35

          4x = 35

            x = 8.75

          3x = 26.25

2) You can solve same as 1.

  120 / 10 = 12    

   set x and x+4

 x + (x + 4) = 12

     2x + 4  = 12

               2x = 8

                 x = 4

         (x + 4) = 8

range =5

step-by-step explanation:

to find the range, we take the largest value and subtract the smallest value.

the largest value is 5

the smallest value is 0

the range is 5-0   =5

step-by-step explanation:

assume that you have 3 different side lengths.   apply the pythagorean theorem here:   square each of the two shortest sides; call them a and b, so that their squares are a² and b².   also square the longest side, calling the result c².

now, if a² + b² = c² is true, the triangle is a right triangle; otherwise it is not a right triangle.