Two consecutive integers are such that their sum is greater than 98 decreased by twice the larger. find the smallest possible values for both integers.

answer:

24 and 26

step-by-step explanation:

x = smaller

x+2 = larger

their sum, x+(x+2), is greater than, > , 98 decreased by, -, twice the

larger, 2(x+2).

so:

x+(x+2) > 98-2(x+2)

  x+x+2 > 98-2x-4

  2x+2 > 94-2x

  2x+2x > 94-2

    4x > 92

      x > 23

since x is the smaller, it must be greater than 23,

and the larger, x+2, must be 25 or larger.

the smallest two such consecutive even integers are 24 and 26.

8

step-by-step explanation:

just put √(2) * √(32) into a calculator. that will make the answer be 8.

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step-by-step explanation: