Find all solutions by transforming the system to reduced echelon form and back substituting. (if there are an infinite number of solutions use s1 as your parameter. if there is no solution, enter no solution.)

2x1 + x2 = 2

−x1 − x2 − x3 = 4

The system has infinite solutions described in the set

Step-by-step explanation:

The augmented matrix of the system is .

We apply row operations:

1. We add the first row to the second row twice and obtain the matrix

2. multiply by -1 the rows of the previous matrix and obtain the matrix that is the reduced echelon form of the matrix associated to the system.

Now we aply backward substitution:

1. Observe that the reduced echelon form has a free variable, then the system has infinite solutions.

2.

3.

.

Then the set of solutions is

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.