Arectangular park is w feet wide. its length is 25 feet larger than its width. record using algebra:
b
what is the length of a fence (including the gates) that was built around the park?

The answer to your question is:  4w + 50

Step-by-step explanation:

Data

w = wide ft

length = w + 25

perimeter = ?

Process

Find the perimeter

Perimeter = 2 wide + 2 length

Perimeter = 2w + 2(w + 25)

Perimeter = 2w + 2w + 50

Perimeter = 4w + 50

answer: two five pound bags one two pound

step-by-step explanation:

maximum area = xy = (16)(32) = 512 ft2

to maximize the area of the garden, the side of the fence parallel to the side of the house should be 32 ft long, and the other two sides should both have length 16 ft.'

source