Does the point (-4, 3) fall on the graph of this line? how do you know? show your work. ( 2 points) ill mark brainliest

Step-by-step explanation:

Since we know the line goes through points and , we can construct a line in slope-intercept form

where is the slope and is the Y-intercept.

The slope can be found using the two points provided:

The line is now represented as

To solve for , we can plug in one of the two points:

We know have our line:

To determine if the point falls on this line, we just plug the numbers into the equation and see if it holds true:

This does not hold true, so the point is not on the line.

it goes right

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen