In △abc, cd is an altitude, such that ad = bc. find ac, if ab = 3 cm, and cd = 3 cm.

answer !

Let AD=BC=x; then BD = 3-x.

Step-by-step explanation:

Then in right triangle BDC the legs are 2 and 3-x and the hypotenuse is x. Use the Pythagorean Theorem to find the value of x.

Then in right triangle ABC the legs are AC and x and the hypotenuse is 3. Use the Pythagorean Theorem again to find the length of AC.

Altitude has property that it falls at right angle.

So, we use pythagoras theorem it both ΔADC and ΔDBC.

In ΔADC

(AC)² = (AD)² + (DC)²

⇒ (AC)² = x² + 9

and in ΔDBC

(BC)² = (BD)² + (DC)²

⇒ x² = (3 - x)² + 9

Substituting this value of x in (AC)²

We get, (AC)² = (3 - x)² + 9 + 9

This is the method to solve this question.

the range is 19

step-by-step explanation:

the range is biggest number minus the smallest, so in this case it would be

41 - 22 = 19

f(x) = y

f(-3) = -5

step-by-step explanation: