Afunction g(x) has x-intercepts at (startfraction 1 over 2 endfraction, 0) and (6, 0). which could be g(x)? g(x) = 2(x + 1)(x + 6) g(x) = (x – 6)(2x – 1) g(x) = 2(x – 2)(x – 6) g(x) = (x + 6)(x + 2)

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step-by-step explanation:

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c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.