Enter the values for the highlighted variables that
show how to subtract the rational expressions
correctly:
2/x2 - 36 - 1/ x^2+6x = 2/(x+6)(x-6) - 1/x(x+a)
=bx/(x+6)(x-6)x - x-c/(x+6)(x-6)x
=dx-x+e/(x+6)(x-6)
= x+f/(x+6)(x-6)
=g/x(x-6)

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

i think the answer is b

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