Which equation represents the line that passes through (–6, 7) and (–3, 6)?

y = –y equals negative startfraction one-third endfraction x plus 9.x + 9
y = –y equals negative startfraction one-third endfraction x plus 5.x + 5
y = –3x – 11y
y = –3x + 25

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen

step-by-step explanation: