After just 4 tenths of a 2.5-mile race was completed, lenox took the lead and remained there until the end of the race.
a. how many miles did lenox lead the race?
b. reid, the second-place finisher, developed a cramp with 3 tenths of the race remaining. how many miles did reid run without a cramp?

Lenox lead the race is = 1.5 miles

Reid run without a cramp = 1.75 miles

Step-by-step explanation:

given data

Lenox lead race =

total race = 2.5 mile =

cramp =

to find out

How many miles did Lenox lead the race and How many miles did Reid run without a cramp

solution

we know Lenox lead =  and total race is 2.5 mile

so

Lenox lead the race is =  of 2.5 mile

Lenox lead the race is = ×

Lenox lead the race is = = 1.5 miles

and

we know developed a cramp with   of the race remaining

so

without cramp race is 1 - =

and run without cramp is of 2.5 mile

Reid run without a cramp =   ×

Reid run without a cramp =  

Reid run without a cramp = 1.75 miles

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5