For which value(s) of k ∈ r, if any, will the following system have (a) no solution, (b) a unique solution, (c) infinitely many solutions
x − 2y + 3z = 2
x + y + z = k
2x − y + 4z = k2

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

its adding 5.5 each time

step-by-step explanation:

no

step-by-step explanation: