Find sec x and sin x if cot x= -1/4 and sin x> 0

answer:

before proving the identities, we need to know the basic identities.

sec(x) = 1 / cos(x)

cot(x) = cos(x) / sin(x)

tan(x) = sin(x) / cos(x)

next is that we want to simplify the left side so that we can obtain the term on the right side.   if the left side equals to right side, then we have proven the identity.

(1 / cos(x)) / [(cos(x) / sin(x)) + (sin(x) / cos(x))] =

(1 / cos(x)) / [(cos2(x) + sin2(x)) / sin(x)cos(x)]

sin2(x) + cos2(x) = 1

(1 / cos(x)) / [1 / sin(x)cos(x)] =

(1 / cos(x)) * (sin(x)cos(x)) =

sin(x)

this side equals the right side.

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|