Dana buys a bag of cookies that contains 6 chocolate chip cookies, 9 peanut butter cookies, 5 sugar cookies and 8 oatmeal raisin cookies. what is the probability that dana randomly selects an oatmeal raisin cookie from the bag, eats it, then randomly selects another oatmeal raisin cookie?

Step-by-step explanation:

In order to solve this problem, we need to start by finding the probability of picking an oatmeal raisin cookies. Probabilities are found by using the following formula:

In this case, our number of desired events is the number of oatmeal raisin cookies we have available: 8.

Our number of possible events is the total number of cookies in the bag, which is:

6+9+5+8=28

so the probability is:

which simplifies to:

Next, we need to find the probability of picking one oatmeal raisin cookie again. This time we only have 7 oatmeal raising cookies and 27 cookies left in the bag, so our probability will now be:

So, the probability of picking an oatmeal raisin cookie at first and picking one of the same kind again is found by multiplying both probabilities.

So the probability that Dana randomly selects an oatmeal raisin cookie from the bag, eats it, then randomly selects another oatmeal raisin cookie is:

all but the second one

step-by-step explanation:

cuz that one goes over 180

mark brainliest