Which is the graph of f(x) = square root of x?

on a coordinate plane, a parabola opens up with a vertex at (0, 0).
on a coordinate plane, an absolute value graph starts at (0, 0) and goes up through (2, 4).
on a coordinate plane, a parabola opens to the right with a vertex at (0, 0).
on a coordinate plane, an absolute value graph starts at (0, 0) and goes up through (4, 2).

Third option given

Step-by-step explanation:

On a coordinate plane, a parabola opens to the right with a vertex at (0, 0).

use the following x values to plot the associated y values on the x-y plane:

If x = 0,  then

If x = 1,  then

If x = 4,  then

If x = 9,  then

Join the points and you will find a branch of a parabola opening to the right.

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

f(x) is going down by 4

step-by-step explanation:

(its either that or its going left by 4)