Given: all snarfs are yelbs. all yelbs are blue.
migs can be either green or pink. some slokes
are snarfs. what conclusion can be drawn?
a. some migs are snarfs.
b. some snarfs are green.
c. some slokes are yelbs.
d. all slokes are migs.

C. Some slokes are yelbs.

Step-by-step explanation:

Given that ;

All snarfs are Yelbs

All Yelbs are Blue

Migs are Green or Pink

Some Slokes are Snarfs

We can see that some Slokes are related to snarfs hence connected to Yelbs

It will be correct to say that some slokes are yelbs

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

probably the last option

step-by-step explanation: