Amachine fills containers with 35 ounces of raisins. after the containers are filled, another machine weighs them. if the container’s weight differs from the desired weight of 35 ounces by more than two ounces, the container is rejected. which graph could be used to determine minimum and maximum acceptable weights for the containers?

hence, the equivalent expression is:

–100k + 3 + 101k = –245 – 181k

equivalent expression is a expression which is similar to the given equation on multiplying by a constant or some constant   factor.

we have to find the equation which is equivalent to the equation:

–k + 0.03 + 1.01k = –2.45 – 1.81k

we multiply both side of the equation by 100 to obtain the equivalent expression as:

hence, the equivalent expression is:

–100k + 3 + 101k = –245 – 181k

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.