Quadrilateral a efgh was dilated by a scale factor of two from the center (1,0) to create e’f’g’h which characteristic of dilations compares segment f’h to segment fh

a.) a segment that passes through the center of dilation in the pre-image continues to pass through the center of dilation in the image

b.) a segment that does not pass through the center of dilation in the pre-image is parallel to the corresponding segments in the image

c.)a segment in the image has the same links as its corresponding segment in the pre-image

d.) a segment that does not pass through the center of dilation in the pre-image is perpendicular to its corresponding segment in the image

B.) A segment that does not pass through the center of dilation in the pre-image is parallel to the corresponding segments in the image

Step-by-step explanation:

Dilation is a Geometric Transformation either enlarges or shrink the figure.

As we can see in the image below, the pre-image is EFGH and the Dilated quadrilateral is labeled as E'F'G'H'. The line segments FH and F'H' are parallel to the center of Dilation, at the point (1,0).

So, the answer is B. For F'H' continues not to pass through the point (1,0).

answer A.) A segment that passes through the center of dilation in the pre-image continues to pass through the center of dilation in the image

B.) A segment that does not pass through the center of dilation in the pre-image is parallel to the corresponding segments in the image

C.)A segment in the image has the same links as its corresponding segment in the pre-image

D.) A segment that does not pass through the center of dilation in the pre-image is perpendicular to its corresponding segment in the image

the correct answer is a.) bc< mn 5 stars if this you : )

step-by-step explanation:

there is only one way to arrange all the eight relative to each other because they are not distinct. we have

now there are nine places to place an (and not more than one in one place).   because we have four symbols, we need to choose four of these nine places to insert an . order does not matter because the are not distinct.

thus there are 1 · c(9,4) ways, or, if we calculate it,

thus there are 126 ways to form such "words."