Let f(x) = x2 − 2x + 2 and g(x) = x − 3. find f(x) ⋅ g(x).

x³ - 5x² + 8x - 6

Step-by-step explanation:

f(x) × g(x)

= (x² - 2x + 2)(x - 3)

Each term in the first factor is multiplied by each term in the second factor, that is

x(x² - 2x + 2) - 3(x² - 2x + 2) ← distribute both parenthesis

= x³ - 2x² + 2x - 3x² + 6x - 6 ← collect like terms

= x³ - 5x² + 8x - 6

x³- 5x² + 8x - 6.

Step-by-step explanation:

Given : f(x) = x2 − 2x + 2 and g(x) = x − 3.

To find : f(x) ⋅ g(x).

Solution : We have given

f(x) = x² − 2x + 2 and g(x) = x − 3.

We need to find the product

f(x) ⋅ g(x).

Plug the values of f(x) and g(x).

( x² − 2x + 2) ( x − 3).

Distribute  x² over (x-3) and 2x over ( x − 3) and 2 over ( x − 3).

x²(x-3) - 2x ( x − 3)+ 2( x − 3).

x³-3x² -2x² + 6x + 2x - 6.

Combine like terms and solve

x³- 5x² + 8x - 6.

Therefore, x³- 5x² + 8x - 6.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐