Acompany installs 5000 light bulbs each with an average life of 500 hours and a deviation of 100 hours. find the percentage of bulbs that can be expected to last the period of time specified assuming the data is normally distributed g

Probability is 0

Step-by-step explanation:

The key information is that the data is normally distributed.

In a normal distribution, each individual value of hours has a probability equals to zero. It is a continuos distribution which is centered in the mean value, and where the expected value is the average.

As the distribution it is centered in the mean value, and it is symmetrical, then the probabilty of a bulb lasting more than the mean value is 0.5, and the probabilty of lasting less than avergare is 0.5 as well, but each individual valu is 0

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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29 is the correct answer

step-by-step explanation: