Find the volume of the solid that lies between planes perpendicular to the x-axis at x = pi/4 and x = 5pi/4. the cross-sections between the planes are circular disks whose diameters run from the curve y = 2 cos x to the curve y = 2 sin x.

The volume of the solid = π²

Step-by-step explanation:

As per the given data of the questions,

The diameter of each disk is  

D = 2 sin(x) - 2 cos(x)

So its radius is

R = sin(x) - cos(x).

The area of each disk is

Now,

Integrate from , we get volume:

After integrate without limit we get

Now after putting the limit, we get

 V = π²

Hence, the required volume of the solid = π²

what is the answer?

unless you made a typo, the answers are both a and c.

step-by-step explanation:

1.5/3 is .5 whereas 3/9 is .3333333 not proportional

22/33 is .66666 and 4/6 is also .66666 proportional

2/4 is .5 whereas 142/213 is .66666 not proportional

14/7 is 2 and 7/3.5 is also 2 proportional

you could've also checked it by doing this simple division:

if the larger fraction divides with the smaller fraction to equal 1, it is proportional. so let me show you what i mean:

when i divide 22/33 by 4/6 i get 1, so we know it is proportional, and it is the same with 14/7 and 7/3.5. now if i divide 3/9 by 1.5/3 i get .66666 so therefore we know it is not proportional.

there are many ways to do this so i wanted to show you some possible ways.