The winner of a 50mile race drove his car to victory at a rate of 100.4893mph. what was his time (to the nearest thousandth of an hour)?

His car's speed rate to the nearest thousandth of an hour is 100.489

Step-by-step explanation:

First: This is the only step, round the speed rate to the nearest thousandth:

When rounding always look at the place value they're telling you to round to and the place value to the right of it. Since, the question wants us to round to the nearest thousandth, look at the thousandths place but more specifically the place value to its right. The thousandths is the third digit behind the decimal point and the one to its right would be the fourth.

100.4893

So, if the number to the thousandths' right is less than 5 turn that number into a zero and keep the rest of the number the same. If the number is greater than or equal to 5 round up by making the number in the thousandths place a digit bigger.

Since 3 is smaller than 5, we'll turn the 3 into a zero and keep the rest the same.

100.4890

Since the zero is behind the decimal point and it is the number farthest to the left we can take it out.

100.489

Thank you for reading

Topic: Rounding, Place Value

well my understanding of this question is they want you to use the y=14.1x -2.3 and put the coordinates they gave you onto the line segment of   y=14.1x -2.3

step-by-step explanation:

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°