Mathematics, 24.09.2019 21:00 karina1466

Which ordered pairs are solutions to the inequality
y−2x≤−3
?
select each correct answer.
(1, −1)
(7, 12)
(−6, −3)
(0, −2)
(5, −3)

Answers: 2

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Answers

Answer from: MorgannJ

(1,-1)

(7,12)

(5,-3)

Step-by-step explanation:

we know that

If a ordered pair is a solution of the inequality, then the ordered pair must satisfy the inequality

we have

$y-2x \leq -3$

Verify each case

case 1) we have

(1,-1)

substitute the value of x and the value of y in the inequality and then compare the results

$-1-2(1) \leq -3$

$-3 \leq -3$ ----> is true

therefore

The ordered pair is a solution of the inequality

case 2) we have

(7,12)

substitute the value of x and the value of y in the inequality and then compare the results

$12-2(7) \leq -3$

$-12 \leq -3$ ----> is true

therefore

The ordered pair is a solution of the inequality

case 3) we have

(-6,-3)

substitute the value of x and the value of y in the inequality and then compare the results

$-3-2(-6) \leq -3$

$9 \leq -3$ ----> is not true

therefore

The ordered pair is not a solution of the inequality

case 4) we have

(0,-2)

substitute the value of x and the value of y in the inequality and then compare the results

$-2-2(0) \leq -3$

$-2 \leq -3$ ----> is not true

therefore

The ordered pair is not a solution of the inequality

case 5) we have

(5,-3)

substitute the value of x and the value of y in the inequality and then compare the results

$-3-2(5) \leq -3$

$-13 \leq -3$ ----> is true

therefore

The ordered pair is a solution of the inequality

Answer from: Quest

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

Answer from: Quest

i can not answer the question due to the fact that you spelled "carton" as "cartoon", a cartoon is something you watch on tv, a carton is a box that holds things. and also you've been waiting for this question for a while so why don't you get off your lazy a** and try to figure it out for yourself for once!

step-by-step explanation:

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look above, and leave your comments down below, and don't for get a five stars and a and brainliest xd

sorry for the stars in the middle of words its because it wouldn't let me submit. xd