Graph f(x) = x2 + 2x - 3, label the function’s x-intercepts, y-intercept and vertex with their coordinates. also draw in and label the axis of symmetry

The given function :

Using completing the squares, we have

       [∵ ]

     (1)

Comparing (1) to the standard vertex form , the vertex of function is at (h,k)=(-1,-4)

For x-intercept, put f(x)=0 in (1), we get

Square root on both sides, we get

∴ x intercepts : x= (-3,0) and (1,0)

For y-intercept put x=0 in (1), we get

∴ y intercept : (0,-3)

Axis of symmetry :

In , a=1 and b=2

Axis of symmetry=

the answer is

a.

x = 42

y = 10

i got it down chief.