(merging of independent pps). let (n1(t))t≥0 and (n2(t))t≥0 be the counting processes of two independent pps of rates λ1 and λ2, respectively. define a new counting process (n(t))t≥0 by n(t) = n1(t)+ n2(t). (7) in this exercise, we show that (n(t))t≥0 ∼ pp(pλ). (i) let τ (1) k , τ (2) k , and τk be the kth inter-arrival times of the counting processes (n1(t))t≥0, (n2(t))t≥0, and (n(t))t≥0. show that τ1 = min(τ (1) 1 ,τ (2) 1 ). conclude that τ1 ∼ exp(λ1 +λ2).

1e+27

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

its totaly b

your welcome btw

isaiah walks 3 miles due north, turns and then 5 miles due east. how far is he from his starting point?

a^2 + b^2 = c^2

let c = distance from starting point.

(3)^2 + (5)^2 = c^2

9 + 25 = c^2

34 = c^2

sqrt{34} = sqrt{c^2}

sqrt{34} = c